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The formula for figuring out the alleged curvature of the Earth

The King James Version (KJV) is mostly used in these lessons. Click here to access the KJV online.
Click here to start the quiz

Question: What is the formula for figuring out the alleged 'curvature' of the Earth? I would like to test this myself.

Answer: If the Earth were a sphere 25,000 miles in circumference, the formula for determining the curvature at a given distance would be 8 inches per mile squared. Examples:

At 58 miles, an object with an elevation of 60 ft. should be hidden behind 2,182 ft. of curvature:

  1. Miles squared = 3,364 (58 x 58)
  2. 3,364 x 8 inches = 26,912 inches
  3. 26,912 inches / 12 = 2,242.67 ft.
  4. 2,242.67 ft. - 60 ft. (elevation of object) = 2,182 ft.

At 42 miles, an object with an elevation of 180 ft. should be hidden behind 996 ft. of curvature:

  1. Miles squared = 1,764 (42 x 42)
  2. 1,764 x 8 inches = 14,112 inches
  3. 14,112 inches / 12 = 1,176 ft.
  4. 1,176 ft. - 180 ft. (elevation of object) = 996 ft.

"The Statue of Liberty in New York stands 326 feet above sea level and on a clear day can be seen as far as 60 miles away. If the Earth were a globe, that would put Lady Liberty at an impossible 2,074 feet below the horizon." (200 Proofs Earth is Not a Spinning Ball, Eric Dubay)

  1. Miles squared = 3,600 (60 x 60)
  2. 3,600 x 8 inches = 28,800 inches
  3. 28,800 inches / 12 = 2,400 ft.
  4. 2,400 ft. - 326 ft. (elevation of object) = 2,074 ft.

Time and time again, it has been demonstrated that there is no measurable or observable curvature. It just isn't there.

Many make the mistake of only calculating 8 inches per mile: https://www.youtube.com/watch?v=6a9wxl6FQbY

WLC Source: https://www.worldslastchance.com/flat-earth/what-is-the-formula-for-figuring-out-the-alleged-curvature.html